{"id":75430,"date":"2023-12-27T22:03:54","date_gmt":"2023-12-27T14:03:54","guid":{"rendered":"https:\/\/www.techphant.cn\/?p=75430"},"modified":"2024-03-27T17:29:10","modified_gmt":"2024-03-27T09:29:10","slug":"syzhsysfdmdyy","status":"publish","type":"post","link":"https:\/\/www.techphant.cn\/blog\/75430.html","title":{"rendered":"\u4f7f\u7528\u6700\u574f\u9002\u5e94\u7b97\u6cd5\u4ee3\u7801\u7684\u5e94\u7528"},"content":{"rendered":"
\u6700\u574f\u9002\u5e94\u7b97\u6cd5\u662f\u4e00\u79cd\u7528\u4e8e\u52a8\u6001\u5206\u533a\u5b58\u50a8\u7ba1\u7406\u7684\u5185\u5b58\u5206\u914d\u7b97\u6cd5\u3002\u4eca\u5929\u6211\u4eec\u5c06\u4ecb\u7ecd\u6700\u574f\u9002\u5e94\u7b97\u6cd5\u7684\u539f\u7406\u4ee5\u53ca\u5728\u5b9e\u9645\u5e94\u7528\u4e2d\u7684\u76f8\u5173\u6848\u4f8b\u3002<\/p>\n
\u6700\u574f\u9002\u5e94\u7b97\u6cd5\u662f\u4e00\u79cd\u7528\u4e8e\u52a8\u6001\u5206\u533a\u5b58\u50a8\u7ba1\u7406\u7684\u7b97\u6cd5\u3002\u5b83\u4e3b\u8981\u7528\u4e8e\u5185\u5b58\u7ba1\u7406\uff0c\u80fd\u591f\u6709\u6548\u5730\u5904\u7406\u52a8\u6001\u53d8\u5316\u7684\u5185\u5b58\u9700\u6c42\u3002\u6700\u574f\u9002\u5e94\u7b97\u6cd5\u7684\u6838\u5fc3\u601d\u60f3\u662f\u9009\u62e9\u6700\u5927\u7684\u53ef\u7528\u5206\u533a\u6765\u6ee1\u8db3\u5f53\u524d\u8bf7\u6c42\uff0c\u8fd9\u6837\u53ef\u4ee5\u6700\u5927\u7a0b\u5ea6\u5730\u51cf\u5c11\u788e\u7247\u95ee\u9898\u3002<\/p>\n
\u6700\u574f\u9002\u5e94\u7b97\u6cd5\u7684\u5b9e\u73b0\u4f9d\u8d56\u4e8e\u5bf9\u53ef\u7528\u5185\u5b58\u5757\u8fdb\u884c\u6392\u5e8f\uff0c\u901a\u5e38\u4f7f\u7528\u4f18\u5148\u961f\u5217\u6216\u5176\u4ed6\u6570\u636e\u7ed3\u6784\u6765\u5b9e\u73b0\u3002\u5f53\u6709\u65b0\u7684\u5185\u5b58\u8bf7\u6c42\u65f6\uff0c\u7b97\u6cd5\u4f1a\u9009\u62e9\u6700\u5927\u7684\u53ef\u7528\u5206\u533a\u6765\u5206\u914d\u7ed9\u8bf7\u6c42\uff0c\u4ee5\u5c3d\u91cf\u51cf\u5c11\u5206\u914d\u540e\u5269\u4f59\u7684\u788e\u7247\u7a7a\u95f4\u3002<\/p>\n
\u4ee5\u4e0b\u662f\u6700\u574f\u9002\u5e94\u7b97\u6cd5\u7684\u7b80\u5355\u4ee3\u7801\u5b9e\u73b0\uff1a<\/p>\n
void worst_fit(int blockSize[], int m, int processSize[], int n) {<\/p>int allocation[n];<\/p>memset(allocation, -1, sizeof(allocation));<\/p> for (int i=0; i= processSize[i]) { if (wstIdx == -1) {<\/p> wstIdx = j;<\/p> } else if (blockSize[wstIdx] < blockSize[j]) {<\/p> wstIdx = j;<\/p> }<\/p> }<\/p> }<\/p> if (wstIdx != -1) {<\/p> allocation[i] = wstIdx;<\/p> blockSize[wstIdx] -= processSize[i];<\/p> }<\/p>}<\/p>\/\/ \u8f93\u51fa\u5206\u914d\u7ed3\u679c<\/p>cout << \"\u8fdb\u7a0b\u53f7 t \u8fdb\u7a0b\u5927\u5c0f t \u5206\u533a\u53f7n\";<\/p> for (int i=0; i<\/n;><\/n;><\/code><\/pre>\n\u6700\u574f\u9002\u5e94\u7b97\u6cd5\u7684\u5e94\u7528<\/h2>\n